P(odd)=0.75
P(even)=0.25
P(3)=0.75/3=1/4
P(6)=0.25/3=1/12
Since 3 and 6 are mutually exclusive,
P(3∪6)=P(3)+P(6)=1/4 + 1/12 = 1/3
A loaded die has the property that the probability of throwing an odd number is three time the probability of throwing an even number. If the even number are equally
likely to appear, find the probability of rolling either a 3 or a 6.
1 answer
1 answer