Asked by rafeh

The loaded cab of an elevator has a mass of 3.0 multiplied by 103 kg and moves 161 m up the shaft in 23 s at constant speed. At what average rate does the force from the cable do work on the cab?

Answers

Answered by bobpursley
tension on cable=3*103*g
work=tension*distance
powerrate=work/time=tension*height/time

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