Asked by Adam

A resistive load of 2 k is connected across the secondary windings of a 25:1 transformer. If the primary voltage is 50 V AC, what will be the secondary current?

im getting 2mA but the correct answer is 1 mA please help
Answered by Henry
Z1 = (25)^2 * 2x = 1250k Ohms
I1 = 50/1250k = 0.04 mA..





































































































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