Asked by Celina
"Find the area of a rhombus with sides of length 10 in. and longer diagonal of length 16 in."
and
Also, how do you solve the problem "Find the area of a regular decagon with radius 4 cm."
and
Also, how do you solve the problem "Find the area of a regular decagon with radius 4 cm."
Answers
Answered by
Henry
2. Decagon: 10 sides.
Area = 2.94*r^2 = 2.94*4^2 = 47 cm^2.
Area = 2.94*r^2 = 2.94*4^2 = 47 cm^2.
Answered by
Henry
1. The diagonal divides the rhombus into 2 congruent triangles. The altitude bisects the diagonal.
(16/2)^2 + Y^2 = 10^2
Y^2 = 100-64 = 36
Y = 6 = Altitude.
Area = 2(16/2 * 6) = 96 in^2.
(16/2)^2 + Y^2 = 10^2
Y^2 = 100-64 = 36
Y = 6 = Altitude.
Area = 2(16/2 * 6) = 96 in^2.
Answered by
EMERIE
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