Asked by Devin

A horse pulls a cart with a force of 145 newtons at an angle of 30 degrees above the horizontal and moves along at a speed of 2.5 m/s. How much work to the nearest kJ does the force do in 6 minutes?
Answered by Henry
d = 2.5m/s * 6min*60s/min = 900 m.

Work = F*d = 145cos30 * 900 = 443,856 J.
= 444 kJ.
Answered by daniel
Vector A has a magnitude of 5.00units,and B has a magnitude of 9.00units.The two vectors make an angle of 50.0degrees with each other .Find A.B.
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