Question
A horse pulls a cart with a force of 145 newtons at an angle of 30 degrees above the horizontal and moves along at a speed of 2.5 m/s. How much work to the nearest kJ does the force do in 6 minutes?
Answers
d = 2.5m/s * 6min*60s/min = 900 m.
Work = F*d = 145cos30 * 900 = 443,856 J.
= 444 kJ.
Work = F*d = 145cos30 * 900 = 443,856 J.
= 444 kJ.
Vector A has a magnitude of 5.00units,and B has a magnitude of 9.00units.The two vectors make an angle of 50.0degrees with each other .Find A.B.
Related Questions
two people pull on separate ropes attached to a cart. the angle between the ropes is 90 degrees and...
The cart of mass 10 kg shown above moves without frictional loss on a level table. A 30 N force pull...
A horse pulls a cart with a force of 180.0 N at and angle of 33.0° with respect to the horizontal an...
A 500 kg horse pulls a cart of mass 1500 kg along a level horizontal road with an acceleration of 1m...