Asked by James

A horse pulls a cart with a force of 40lb at an angle of 30 degrees above the horizontal and moves along at a speed of 6mi/hr. A) how much work does the force do in 10 min? B) What is the average power (in horsepower) of the force?
Answered by drwls
A) (Force component along direction of motion) * 5280 ft = ___ ft lb

B) (Force component along direction of motion) * (speed, in ft/s) = ___ ft lb/s

Use the conversion factor 550 ft lb/s per HP. Also convert 6 mi/h to 8.8 ft/s
Answered by janet
a-642,648.7029 ft.lb
b- 823.9085934 W
Answered by nimo
i want 1nd qus
Answered by Muhammad Essa
(a)1.8*10^5 ft.lb (b)0.55 hp
Answered by Sana
Plz give the answer
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