Asked by Anonymous
Automobile air bags employ a chemical reaction involving the rapid decomposition of sodium azide
(NaN3) into sodium metal and nitrogen gas to inflate in a collision. How much sodium azide is required
to decompose to inflate a 20.0 L air bag? Assume that the gas is at standard temperature and pressure, and
thus occupies 22.4 L per mole.
a. 76.3 g
b. 42.8 g
c. 38.7 g
d. 62.7 g
(NaN3) into sodium metal and nitrogen gas to inflate in a collision. How much sodium azide is required
to decompose to inflate a 20.0 L air bag? Assume that the gas is at standard temperature and pressure, and
thus occupies 22.4 L per mole.
a. 76.3 g
b. 42.8 g
c. 38.7 g
d. 62.7 g
Answers
Answered by
DrBob222
See the post on limestone. All of these stoichiometry problems are worked the same way.
Answered by
thegame
=38.7 g (c)
Steps
20/22.4= 0.89 mols of NaN3
Balanced Equation
2(NaN3) --> 2(Na) + 3(N2)
Looking for mols of n2
So 2(0.89)/3= mols of n2 =0.59 mol
Then molar mass of NaN3 = 65
0.59x65= 38.7 g
Steps
20/22.4= 0.89 mols of NaN3
Balanced Equation
2(NaN3) --> 2(Na) + 3(N2)
Looking for mols of n2
So 2(0.89)/3= mols of n2 =0.59 mol
Then molar mass of NaN3 = 65
0.59x65= 38.7 g
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.