thegame

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Answers

The following answers were posted by visitors named thegame.

=38.7 g (c) Steps 20/22.4= 0.89 mols of NaN3 Balanced Equation 2(NaN3) --> 2(Na) + 3(N2) Looking for mols of n2 So 2(0.89)/3= mols of n2 =0.59 mol Then molar mass of NaN3 = 65 0.59x65= 38.7 g
9 years ago