Question

(x+1)/(x+3)(x-3) + 4(x-3)/(x-3)(x+3) + (x-1)(x-3)/ (3-x)(x+3) please explain how you get it

Answer 1

Since that is not an equation, and I have no idea what problem it is supposed to be the solution of, I cannot explain how you or anyone "got" it.

If you post this again in more complete form, please use brackets to clarify what the denominators are.

Answer 2

ok the question is [(x+1) divided by (x+3)(x-3)] plus [4(x-3) divided by (x-3)(x+3)] plus [(x-1)(x-3) divided by (3-x)(x+3)] i am not really sure how else to explain it. it is adding rational expression with 3 different fractions all added together. i need to get a common denominator. please if possible show me how you get the answer.. sorry if you cant understand it

Answer 3

Did you notice that your denominators are "almost" the same already??

If the factor in the last fraction had been (x-3) instead of (3-x) you would be all set.
Well, why don't we make the last term from
..+ (x-1)(x-3)/[(3-x)(x+3)] to
..- (x-1)(x-3)/[(x-3)(x+3)]

(notice I multiplied top and bottom by -1)

now just expand your numerators, collect all like terms and you are done.

Answer 4

wouldnt that make the bottom one be (x-3)(x-3) since you would have to multiply both of the bottom terms by -1

Answer 5

no
if you multiply both, then you are in effect multiplying by (-1) by (-1), which would produce no change at all

eg. if you multiply (3)(4) by -1 would you multiply both??