Asked by Eys
Diffraction from an unknown cubic metal is observed to occur at the following values of θ when using CuKα radiation. Determine the crystal structure to find the lattice constant.
20.1⁰, 29.2⁰, 36.6⁰, 43.5⁰, 50.2⁰, 57.4⁰, 65.5⁰
a) What is the crystal structure?
SC, BCC or FCC
b)Express the value of the lattice constant in m
20.1⁰, 29.2⁰, 36.6⁰, 43.5⁰, 50.2⁰, 57.4⁰, 65.5⁰
a) What is the crystal structure?
SC, BCC or FCC
b)Express the value of the lattice constant in m
Answers
Answered by
himani.
a. BCC
Answered by
bonjo
i think b only ask for the expression, not the actual value????...beside, in order to get the actual value of lattice constant, we need the radius...is the radius given or can it be determined???...
i tried expressing the lattice constant for the BCC as 4r/sqrt3 but can't get the correct format.
i tried expressing the lattice constant for the BCC as 4r/sqrt3 but can't get the correct format.
Answered by
Eys
The value of the radius is not given
Answered by
Elena
For CuKα-radiation λ=1.541•10⁻¹⁰ m.
From equation
sin²θ₁/(h²+k²+l²)₁=sin²θ₂/(h²+k²+l²)₂=…. const,
sin²θ₁/1= sin²θ₂/2= sin²θ₃/3=… sin²θ ₇/7.
For the given data
0.118/1 = 0.238/2=0.3555/3=0.4738/4=0.59/5=
=0.7097/6=0.828/7=0.118 =>
The crystal structure is simple cubic –SC.
sin²θ/(h²+k²+l²)=const=λ²/4a²
a= sqrt{λ²(h²+k²+l²)/2sin²θ }= >
a= sqrt{λ²(1²+0²+0²)₁/2sin²θ₁}=
= sqrt{(1.541•10⁻¹⁰)²(1²+0²+0²)/2sin²20.1⁰}=3.17•10⁻¹⁰m.
From equation
sin²θ₁/(h²+k²+l²)₁=sin²θ₂/(h²+k²+l²)₂=…. const,
sin²θ₁/1= sin²θ₂/2= sin²θ₃/3=… sin²θ ₇/7.
For the given data
0.118/1 = 0.238/2=0.3555/3=0.4738/4=0.59/5=
=0.7097/6=0.828/7=0.118 =>
The crystal structure is simple cubic –SC.
sin²θ/(h²+k²+l²)=const=λ²/4a²
a= sqrt{λ²(h²+k²+l²)/2sin²θ }= >
a= sqrt{λ²(1²+0²+0²)₁/2sin²θ₁}=
= sqrt{(1.541•10⁻¹⁰)²(1²+0²+0²)/2sin²20.1⁰}=3.17•10⁻¹⁰m.
Answered by
marcia
3.17*10^-10
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.