Asked by Rach

A diffraction grating gives a second-order maximum at as angle of 31‹ for violet light (ƒÉ = 4.0 ~ 102 nm). If the diffraction grating is 1.0 cm in width, how many lines are on this diffraction grating?

Answers

Answered by Rach
Sorry about the double post, and
the question is:
A diffraction grating gives a second-order maximum at as angle of 31 degrees for violet light (wavelength = 4.0 x 102 nm). If the diffraction grating is 1.0 cm in width, how many lines are on this diffraction grating?
Answered by bobpursley
n lambda = d sin( theta )

d=n * lambda/sinTheta

solve for d. That is the distance between slits, so lines/distance= 1/d

change wavelength to cm if you want lines per cm
Answered by Rach
isn't that derived from the formula used for single slit though? and this is multiple slit (isn't that the same eqns as double slit?
Answered by Rach
so n= 2 (second order)
theta= 31 degrees
d= 0.1 m
lambda= 4.0 x 10^-7 m

(i'm required to solve in m)

is this correct?
Answered by Anonymous
no
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