Asked by Rach
A diffraction grating gives a second-order maximum at as angle of 31‹ for violet light (ƒÉ = 4.0 ~ 102 nm). If the diffraction grating is 1.0 cm in width, how many lines are on this diffraction grating?
Answers
Answered by
Rach
Sorry about the double post, and
the question is:
A diffraction grating gives a second-order maximum at as angle of 31 degrees for violet light (wavelength = 4.0 x 102 nm). If the diffraction grating is 1.0 cm in width, how many lines are on this diffraction grating?
the question is:
A diffraction grating gives a second-order maximum at as angle of 31 degrees for violet light (wavelength = 4.0 x 102 nm). If the diffraction grating is 1.0 cm in width, how many lines are on this diffraction grating?
Answered by
bobpursley
n lambda = d sin( theta )
d=n * lambda/sinTheta
solve for d. That is the distance between slits, so lines/distance= 1/d
change wavelength to cm if you want lines per cm
d=n * lambda/sinTheta
solve for d. That is the distance between slits, so lines/distance= 1/d
change wavelength to cm if you want lines per cm
Answered by
Rach
isn't that derived from the formula used for single slit though? and this is multiple slit (isn't that the same eqns as double slit?
Answered by
Rach
so n= 2 (second order)
theta= 31 degrees
d= 0.1 m
lambda= 4.0 x 10^-7 m
(i'm required to solve in m)
is this correct?
theta= 31 degrees
d= 0.1 m
lambda= 4.0 x 10^-7 m
(i'm required to solve in m)
is this correct?
Answered by
Anonymous
no
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