Asked by mysterychicken
1. Find the product of the solutions of this equation:
1 / x+1 - 6-x/6x = 0
2. If y is jointly proportional to x and z and y = 4 when x = 8 and z = 1, what is the value of y when x = 24 and z = 3?
For this one I think I'm solving it wrong, because I keep getting the answer as y=12, and that's not even one of my choices.
1 / x+1 - 6-x/6x = 0
2. If y is jointly proportional to x and z and y = 4 when x = 8 and z = 1, what is the value of y when x = 24 and z = 3?
For this one I think I'm solving it wrong, because I keep getting the answer as y=12, and that's not even one of my choices.
Answers
Answered by
Steve
If you mean
1/(x+1) - (6-x)/(6x) = 0 then
1/(x+1) = (6-x)/(6x)
6x = (6-x)(x+1)
6x = -x^2+5x+6
x^2 + x - 6 = 0
product of roots = -6
y = kxz
4 = k(8)(1)
k = 1/2, so
y = xz/2
y = 24*3/2 = 36
1/(x+1) - (6-x)/(6x) = 0 then
1/(x+1) = (6-x)/(6x)
6x = (6-x)(x+1)
6x = -x^2+5x+6
x^2 + x - 6 = 0
product of roots = -6
y = kxz
4 = k(8)(1)
k = 1/2, so
y = xz/2
y = 24*3/2 = 36
Answered by
mysterychicken
Ohhh I get it now! Thanks alot for clearing it up
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