Question
a 10kg table needs to be pushed across the floor (µ=3). u stand behind it and push it at an anjgle of 30 degrees down with a force of 60N. wats the acceleration of the table?
Answers
drwls
That is a very high coefficient of friction. Are you sure it is 3 and not 0.3? If it is 3, it won't move.
The downward force on the floor is
Fn = M g + 60 sin 30 = 128 N
The friction force is
Ff = µ * Fn
The acceleration is (60 cos 60 - Ff)/M
The downward force on the floor is
Fn = M g + 60 sin 30 = 128 N
The friction force is
Ff = µ * Fn
The acceleration is (60 cos 60 - Ff)/M