Asked by Colin
a 10kg table needs to be pushed across the floor (µ=3). u stand behind it and push it at an anjgle of 30 degrees down with a force of 60N. wats the acceleration of the table?
Answers
Answered by
drwls
That is a very high coefficient of friction. Are you sure it is 3 and not 0.3? If it is 3, it won't move.
The downward force on the floor is
Fn = M g + 60 sin 30 = 128 N
The friction force is
Ff = µ * Fn
The acceleration is (60 cos 60 - Ff)/M
The downward force on the floor is
Fn = M g + 60 sin 30 = 128 N
The friction force is
Ff = µ * Fn
The acceleration is (60 cos 60 - Ff)/M
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.