Question
In figure p4.36, m1 = 10kg and m2 = 4.0kg. the coefficient of static friction between m1 and the horizontal surface is 0.50, and the coefficient of kinetic friction is 0.30. (a) if the system is released from rest, what will its acceleration be? (b) if the system is set in motion with m2 moving downward, what will be the acceleration of the system?
Answers
Anonymous
b.) M2g- μk M1g = (M1+ M2) a1
A1= (M2g- μk M1g )/(M1+ M2)
A1= ((4.0 kg) (9.8) – (0.30) (9.8) (10) )/(10+4)
A1= 0.7 m/s2
A1= (M2g- μk M1g )/(M1+ M2)
A1= ((4.0 kg) (9.8) – (0.30) (9.8) (10) )/(10+4)
A1= 0.7 m/s2