Asked by Sarah
Are these formulas correct?
pH + pOH = 14
pH = -log[H+]
pOH = -log[OH-]
[OH-] = 10^-pOH
pH = 10^-pH
pH + pOH = 14
pH = -log[H+]
pOH = -log[OH-]
[OH-] = 10^-pOH
pH = 10^-pH
Answers
Answered by
DrBob222
all ok.
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