Question

- A copper cylinder is initially at 20.0oC. At what temperature will its volume be 0.15% larger than it is at 20.0oC? Take: ƒÒcofficient of thermal expansion of volume for cu= 5.1x10-5 /C

Answer 1

ΔV/V = αΔT,
ΔT = ΔV/ α•V=
=0.0015V/V•5.1•10⁻⁵=
=0.0015 / 5.1•10⁻⁵= 29.4,
t=20+29.4 =49.4℃

Answer 2

Thank you ^__^

Answer 3

123