Asked by Mqureshi
If 50.0grams of copper initially at 145.0 C is put into 150.0mL of water initially at 25.00C, then what will the final temperature of the mixture be? assume that all of the heat lost by the hot copper is absorbed by the cold water.
Answers
Answered by
DrBob222
heat lost by Cu + heat gained by H2O = 0.
[(mass Cu x specific heat Cu x (Tfinal-Tinitial)] + [(mass H2O x specific heat H2O x (Tfinal-Tinitial)] = 0
[(mass Cu x specific heat Cu x (Tfinal-Tinitial)] + [(mass H2O x specific heat H2O x (Tfinal-Tinitial)] = 0
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