If is a n acute angle and tanx=3 4 evaluate cosx-sinx cosx+sinx

8 answers

if tanx = 3/4,
sinx = 3/5
cosx = 4/5

and go from there
the ans
2+2-4
4/5-3/5 divided by 4/5+3/5
Then go from there
If x is an acute angle and tan x = 3/4 evaluate cos x_sin x cos x+sin x
I can't get it
I got it
Up if x is an actue angle and tan x° 3/4 evaluate cosx - since/cosx+sinx
Similar Questions
  1. Simplify #3:[cosx-sin(90-x)sinx]/[cosx-cos(180-x)tanx] = [cosx-(sin90cosx-cos90sinx)sinx]/[cosx-(cos180cosx+sinx180sinx)tanx] =
    1. answers icon 1 answer
  2. Trigonometric IdentitiesProve: (tanx + secx -1)/(tanx - secx + 1)= tanx + secx My work so far: (sinx/cosx + 1/cosx +
    1. answers icon 0 answers
    1. answers icon 0 answers
    1. answers icon 0 answers
more similar questions