Asked by anonymous
simplify the following. leave answers with positive exponents
1) c^2 x c^7= c^9
2) (2w^2 x^4)^3= (2w^5 x^7)
3)(a^4)^12= a^16
4) 28x^2/ y^-9= i don't undestand this
5) (3b)^3= 3b^4
6) x^14/x^6= x^8
7) 977^0= 977
8) (x/y)^8= i don't understand
1) c^2 x c^7= c^9
2) (2w^2 x^4)^3= (2w^5 x^7)
3)(a^4)^12= a^16
4) 28x^2/ y^-9= i don't undestand this
5) (3b)^3= 3b^4
6) x^14/x^6= x^8
7) 977^0= 977
8) (x/y)^8= i don't understand
Answers
Answered by
anonymous
3) = a^48
Answered by
anonymous
2) =(2w^6 x^12)
Answered by
anonymous
7=1
8= x^8/y^8
4=28x^2 y^9
8= x^8/y^8
4=28x^2 y^9
Answered by
MathMate to Mercy
Considering the corrections that you subsequently posted,
1,2,3,6,7 are correct, well-done!
For #4,#8
we use the law of exponent that a negative exponent is equal to it's reciprocal, for example:
5/y^(-3) = 5*y³
For #5, we use the rule:
(xy)^a = x^a y^a
For example:
(3x)² = 3² x² = 9x²
Hope that helps.
1,2,3,6,7 are correct, well-done!
For #4,#8
we use the law of exponent that a negative exponent is equal to it's reciprocal, for example:
5/y^(-3) = 5*y³
For #5, we use the rule:
(xy)^a = x^a y^a
For example:
(3x)² = 3² x² = 9x²
Hope that helps.
Answered by
anonymous
5) =27b^3
4) =28x^2 y^9
8= x^8 y^8 so its not x^8/y^8
4) =28x^2 y^9
8= x^8 y^8 so its not x^8/y^8
Answered by
anonymous
i have four questions
1) 1/5^-3= 1/125
2) (7d^4/df^5) * (d^6/f^5)= 7d^9/f^10
3) -6x^8y^-8= 6x^8 y^8 or -6x^8/y^8
4) 3t^4v^3/21t^2v^6= t^2 7y^3 or t^2/7y^3
1) 1/5^-3= 1/125
2) (7d^4/df^5) * (d^6/f^5)= 7d^9/f^10
3) -6x^8y^-8= 6x^8 y^8 or -6x^8/y^8
4) 3t^4v^3/21t^2v^6= t^2 7y^3 or t^2/7y^3
Answered by
MathMate
#4 and #5 are both correct.
For #8, it <i>is</i> x^8/y^8, since the question requires positive exponents.
(You <i>could</i> have written it as x^8y^-8.)
1. 1/125 is 1/5^3. See if you can find the correct answer.
2. d^4*d^6 is d^10, so correction required.
3. the minus sign before the numbers is the sign, and the minus sign in the exponent is not affected by the sign of the expression. So
-6x^8y^-8= -6x^8/y^8
4. 3t^4v^3/21t^2v^6= t^2/7y^3 except that the last variable (y) should have been a "v".
For #8, it <i>is</i> x^8/y^8, since the question requires positive exponents.
(You <i>could</i> have written it as x^8y^-8.)
1. 1/125 is 1/5^3. See if you can find the correct answer.
2. d^4*d^6 is d^10, so correction required.
3. the minus sign before the numbers is the sign, and the minus sign in the exponent is not affected by the sign of the expression. So
-6x^8y^-8= -6x^8/y^8
4. 3t^4v^3/21t^2v^6= t^2/7y^3 except that the last variable (y) should have been a "v".
Answered by
anonymous
ok thank you
Answered by
MathMate
You're welcome!
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