Asked by Holly

107. Evaluate: logx 16 = -2

a. 0.25
b. 4
c. -4
d. -0.25

108. Evaluate: e2 ln 3

a. 6
b. 9
c. 12
d. 18
Answered by Steve
107. Solve
log_x 16 = -2
16 = x^-2
16 = 1/x^2
x = 1/4


108.
e^(2 ln 3)
(e^ln 3)^2
3^2
9
Answered by Holly
thaanks ;3
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