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Asked by NIck

4x^2+24x+128y-988=0 in standard form
12 years ago

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Answered by Steve
128y = -4x^2 - 24x + 988
32y = -x^2 - 6x + 247
32y = -(x^2+6x+9) + 247+9
32y = -(x+3)^2 + 256
y = -1/32 (x+3)^2 + 8
12 years ago
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4x^2+24x+128y-988=0 in standard form

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