Asked by Sarah
                4.	Write the expression for Ka for the ionization of acetic acid in water.
            
            
        Answers
                    Answered by
            Sarah
            
    Write the expression for Ka for the ionization of acetic acid in water.
    
                    Answered by
            DrBob222
            
    CH3COOH ==> CH3COO^- + H^+
Ka = (H^+)(CH3COO^-)/(CH3COOH)
    
Ka = (H^+)(CH3COO^-)/(CH3COOH)
                    Answered by
            Sarah
            
    When I calculate the percent difference between your value for Ka and the accepted value, what could be two sources of error that might account for any differences?
    
                    Answered by
            DrBob222
            
    I'm sorry but I don't understand the question. I didn't give you a value for Ka so how can there be a difference? I gave you the Ka expression but not a value for Ka. 
    
                    Answered by
            isaa
            
    Ka= [H3O^+][CH3COO^-] / [CH3COOH]
    
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