4. Write the expression for Ka for the ionization of acetic acid in water.

5 answers

Write the expression for Ka for the ionization of acetic acid in water.
CH3COOH ==> CH3COO^- + H^+

Ka = (H^+)(CH3COO^-)/(CH3COOH)
When I calculate the percent difference between your value for Ka and the accepted value, what could be two sources of error that might account for any differences?
I'm sorry but I don't understand the question. I didn't give you a value for Ka so how can there be a difference? I gave you the Ka expression but not a value for Ka.
Ka= [H3O^+][CH3COO^-] / [CH3COOH]