Asked by Sarah

4. Write the expression for Ka for the ionization of acetic acid in water.
Answered by Sarah
Write the expression for Ka for the ionization of acetic acid in water.
Answered by DrBob222
CH3COOH ==> CH3COO^- + H^+

Ka = (H^+)(CH3COO^-)/(CH3COOH)
Answered by Sarah
When I calculate the percent difference between your value for Ka and the accepted value, what could be two sources of error that might account for any differences?
Answered by DrBob222
I'm sorry but I don't understand the question. I didn't give you a value for Ka so how can there be a difference? I gave you the Ka expression but not a value for Ka.
Answered by isaa
Ka= [H3O^+][CH3COO^-] / [CH3COOH]