oops, I made a mistake.
y= -4.9t^2 + 68.6t
An object is fired vertically upward with an initial speed of 68.6 meters/second. After t seconds, the height is shown by
y = -49 t^2 + 68.6 t meters. Given that this object has an initial speed of 68.6 m/s, what is the maximum height it will reach?
2 answers
See
http://www.jiskha.com/display.cgi?id=1369047938
http://www.jiskha.com/display.cgi?id=1369047938