Question

A group of 30 people consists of 15 children, 10 men, and 5 women. Tom and Jerry are two of the men in the group. Five people are picked at random without replacement.

2A - Find the chance the first person picked is a man, given that the fourth and fifth people picked are children.

2B - Find the chance that more than two women are picked.

2C - Find the chance that Tom and Jerry both get picked.

Answers

hehe
cheating for final exam stat 2.2x eh? :D i want the answer too!!! :P
Jabang
2b : .40189
PsyDAG
A. If it is the first pick, it doesn't matter what the subsequent picks are, 10/30.

B. More than two women means 3, 4 or 5 women.

If the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of the individual events.

For 5 women, P = 5/30 * 4/29 * 3/28 * 2/27 * 1/26 = ?

For 4 women, P = 5/30 * 4/29 * 3/28 * 2/27 * 25/26 = ?

For 3 women, P = ?

Either-or probabilities are found by adding the individual probabilities.

C. P = 1/30 * 1/29 = ?
Din123
2B is 0.40189 is wrong
Emerald
2C is also wrong.
Pebbles
2a is 10/28
David12
2B : Hypergyometric: N=30, G=5, n=5, g>=3

Value: 2.193%
David12
2C : Again Hypergeometry

2 Good items (Tom & Jerry).

So in 2C, N=30, G=2, n=5, g=2
Probability = 0.0299 = 0.023
yogesh
2b .3571
2c ?
yogesh
sorry 2a .3571
2b .0229 ?
nancy
is that 2C = 0.0229885?
seriously
LOL. Yes. You guys really know your probability. And what are you going to do with your certificate? Use it as toilet paper? Well that's about all it's good for. You've made sure of that.
Din123
Plz, does anyone know what is the answer?
Dave
C. 0.0229 is the correct one
Din123
thanks Dave
Help
a) 0.3571
b).02193
c).0229

Related Questions