Asked by Anubhav
ABC is a triangle with a right angle at
A.M and N are points on BC such that AM is the altitude, and AN is the
angle bisector of ∠BAC. If CN/NB=21,what is CM/MB?
A.M and N are points on BC such that AM is the altitude, and AN is the
angle bisector of ∠BAC. If CN/NB=21,what is CM/MB?
Answers
Answered by
Reiny
Have been working on it, hard sketch to make, unless I am missing something.
so far I have:
BC = 22
AB = √242/29
AC = 41√242/29
sin (angle ANC) = exactly 22/29
(when I sketched this, it made no sense)
will not be able to get back to it until tonight, if you have the patience to wait.
so far I have:
BC = 22
AB = √242/29
AC = 41√242/29
sin (angle ANC) = exactly 22/29
(when I sketched this, it made no sense)
will not be able to get back to it until tonight, if you have the patience to wait.
Answered by
Reiny
I have a solution, but what a mess.
Before I type it all out, let me know if you still need the solution. I certainly don't feel like typing it all out unless you will actually look at it.
Before I type it all out, let me know if you still need the solution. I certainly don't feel like typing it all out unless you will actually look at it.
Answered by
Dan
Yes please Reiny. It would help me a lot. Thanks! :)
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