Asked by Vicki
How many grams of barium nitrate is needed to form a solution with 5.00 mass% Ba (NO3)2 in 400 grams of water.
Answers
Answered by
DrBob222
% by mass = (mass solute/g soln)*100
let x = mass solute
[(x)/(400+x)]*100 = 5
Solve for x.
let x = mass solute
[(x)/(400+x)]*100 = 5
Solve for x.
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