Asked by Anonymous
10.0 grams of barium chloride (208.3g/mol) is reacted with excess potassium phosphate and 7.22 of grams of barium phosphate (601.8 g/mol) is isolated. calculate the theoretical yield of barium phosphate
Answers
Answered by
bobpursley
I suspect a balanced equation is the place to start...
3BaCl2 + 2K3PO4 >>> Ba3(PO4)2 + 6KCl
moles barium phosphate: 1/3 *moles barium chloride
calcuate the moles barium chloride, divide by three, then that is the moles of barium phosphate, convert that to grams of barium phosphate.
3BaCl2 + 2K3PO4 >>> Ba3(PO4)2 + 6KCl
moles barium phosphate: 1/3 *moles barium chloride
calcuate the moles barium chloride, divide by three, then that is the moles of barium phosphate, convert that to grams of barium phosphate.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.