ME = 2 sqrt(.56(1-.56)/400)
= 2 sqrt(.56(.44)/400)
= 2 sqrt(.2464/400)
= 2 sqrt(0.000616)
= 2 x .0248
= 0.0496
or
4.96 percent margin of sampling error
In an election poll, 56% of voters chose a certain candidate. find the margin of sampling error.
So far I have: ME=2sqrt0.56(1-0.56)/400 but I don't know how to finish the problem.
Any help would be great!
2 answers
in an election poll,56% of 400 voters choose a certain candidate, find the margin of sampling error.
2 answers