Asked by Laura
supposed that a liter of sample water contains 1.00 mmol of Ca2+ ions and 1.50 mmol HCO3- ions. how many millimoles of CaCO3 will precipitate if this water is boiled for 15 mins?
Answers
Answered by
DrBob222
.......Ca^2+ + 2HCO3^- ==> Ca(HCO3)2
I.......1.0.....1.5..........0
Which is the limiting reagent?
1 mmol Ca^2+ will form 1 mmols Ca(HCO3)2
1.5 mmol HCO3^- will form 0.75 mmols Ca(HCO3)2; therefore, 0.75 mmols Ca(HCO3)2 will be formed.
Then Ca(HCO3)2 ==> CaCO3 + H2O + CO2
0.75 mmols Ca(HCO3)2 will form 0.75 mmols CaCO3. Convert that to grams CaCO3.
I.......1.0.....1.5..........0
Which is the limiting reagent?
1 mmol Ca^2+ will form 1 mmols Ca(HCO3)2
1.5 mmol HCO3^- will form 0.75 mmols Ca(HCO3)2; therefore, 0.75 mmols Ca(HCO3)2 will be formed.
Then Ca(HCO3)2 ==> CaCO3 + H2O + CO2
0.75 mmols Ca(HCO3)2 will form 0.75 mmols CaCO3. Convert that to grams CaCO3.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.