Asked by Anon
                A meter stick is suspended vertically at a pivot point 27 cm from the top end. It is rotated on the pivot until it is horizontal and then released from rest. What will be its maximum angular velocity (in radians/second)?
            
            
        Answers
                    Answered by
            Damon
            
    potential energy at horizontal = m g h = m (9.81)(.50-.27) = 2.26 m Joules
kinetic energy at vertical = (1/2)I omega^2
I = m (1/12)(1^2) + m (.23)^2
= m (.136)
so
I omega^2 = .136 m omega^2
omega^2 = 2.26/.136
omega = 4.08 radians/second
    
kinetic energy at vertical = (1/2)I omega^2
I = m (1/12)(1^2) + m (.23)^2
= m (.136)
so
I omega^2 = .136 m omega^2
omega^2 = 2.26/.136
omega = 4.08 radians/second
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