Asked by Anon
A meter stick is suspended vertically at a pivot point 27 cm from the top end. It is rotated on the pivot until it is horizontal and then released from rest. What will be its maximum angular velocity (in radians/second)?
Answers
Answered by
Damon
potential energy at horizontal = m g h = m (9.81)(.50-.27) = 2.26 m Joules
kinetic energy at vertical = (1/2)I omega^2
I = m (1/12)(1^2) + m (.23)^2
= m (.136)
so
I omega^2 = .136 m omega^2
omega^2 = 2.26/.136
omega = 4.08 radians/second
kinetic energy at vertical = (1/2)I omega^2
I = m (1/12)(1^2) + m (.23)^2
= m (.136)
so
I omega^2 = .136 m omega^2
omega^2 = 2.26/.136
omega = 4.08 radians/second