Asked by Jem
A meter stick is supported at its center. If a load of 150 dynes is placed at the 20 cm mark, where should a 100 dynes load be placed in order that the stick remains in the horizontal position?
Answers
Answered by
Elena
Torque= force • distance
150 • (0.5-0.2) = 100 • x
x= 150•0.3/100=0.45 m (from the center or at the point 0.95 m mark)
150 • (0.5-0.2) = 100 • x
x= 150•0.3/100=0.45 m (from the center or at the point 0.95 m mark)
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