Ask a New Question

Question

A meter stick is supported at its center. If a load of 150 dynes is placed at the 20 cm mark, where should a 100 dynes load be placed in order that the stick remains in the horizontal position?
12 years ago

Answers

Elena
Torque= force • distance
150 • (0.5-0.2) = 100 • x
x= 150•0.3/100=0.45 m (from the center or at the point 0.95 m mark)
12 years ago

Related Questions

Suppose you have a meter stick with two masses attached. The mass m1 is 0.60 kg and it is located at... Suppose that a meter stick is balanced at its center. A 0.27-kg is positioned at 18 cm from the left... a meter stick of wight 0.8 n is pivoted at 40 cm mark at which mark 1n load should be located to bal... In lab, a meter stick has its center of gravity at the 45.5 mark. The stick is supported with a mete... One end of a meter stick is pinned to a table, so the stick can rotate freely in a plane parallel to... A certain meter stick is calibrated in millimeters (the distance between two consecutive marks is ON... 1. Suspend the meter stick by a string from its center. 2. Notice carefully where it balances. It p... A meter stick is positioned on a horizontal table top such that the 100cm end extends over the edge... A stick is supported at the centre, and a block of 5kg is hung at the 80-cm mark. Another block is a... Maria is using am meter stick to determine the height of a door if the smallest unit on the meter st...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use