Question

a meter stick of wight 0.8 n is pivoted at 40 cm mark at which mark 1n load should be located to balence the sticke

Answer 1

Please type your <u>subject</u> in the <b>School Subject</b> box. Any other words, <u>including obscure abbreviations</u>, are likely to delay responses from a teacher who knows that subject well.

Answer 2

Since the stick by itself is unbalanced with the fulcrum off center, the weight must be placed on the short (40 cm) side. Let x be the distance of the 1 N weight from the fulcrum, measured toward the short end, in cm. The stick's weight acts at the center of mass at x = -10 cm

0.8*(-10) + 1*x = 0 at equilbrium

x = 8 cm

Answer 3

0.8*40-1x=0
x=32cm