Asked by Grant
A ladder 10 m long rests on horizontal ground and leans against a
vertical wall. The foot of the ladder is pulled away from the wall at 2
m/s. How fast is the top sliding down the wall when the foot of the
ladder is 6m from the wall?
vertical wall. The foot of the ladder is pulled away from the wall at 2
m/s. How fast is the top sliding down the wall when the foot of the
ladder is 6m from the wall?
Answers
Answered by
Reiny
x^2 + y^2 = 100 , where x is the base, y the height
2x dx/dt + 2y dy/dt = 0
given: dx/dt = 2 , and x = 6
then 36+y^2 = 100
y^2 = 64
y = 8
in
2x dx/dt + 2y dy/dt = 0
2(6)(2) + 2(8)dy/dt = 0
dy/dt = -24/16 = -3/2
it is sliding down at 3/2 m/sec
2x dx/dt + 2y dy/dt = 0
given: dx/dt = 2 , and x = 6
then 36+y^2 = 100
y^2 = 64
y = 8
in
2x dx/dt + 2y dy/dt = 0
2(6)(2) + 2(8)dy/dt = 0
dy/dt = -24/16 = -3/2
it is sliding down at 3/2 m/sec
Answered by
solomon
Let x represent the length of the ladder =10meters+5meters=x =x=10m+5m =15m :the length of the ladder is 10m
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