Asked by sol
evaluate the limit as x approaches 0 (1/x/-1/sins)
Answers
Answered by
Steve
1/x - 1/sinx
=(sinx - x)/(x sinx)
Now take derivatives
(cosx - 1)/(sinx + x cosx)
and again
-sinx/(cosx + cosx - x sinx)
as x->0 you get
0/2 = 0
=(sinx - x)/(x sinx)
Now take derivatives
(cosx - 1)/(sinx + x cosx)
and again
-sinx/(cosx + cosx - x sinx)
as x->0 you get
0/2 = 0
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