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Asked by Anonymous

evaluate the limit as x approaches positive and negative infinity (x^2+6x+8)/(x+3)^2
15 years ago

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Answered by bobpursley
factor:

(x+4)(x+2)/(x+3)(x+3)

divide numerator and denominator by x^2

(1+4/x)(1+2/x)/(1+3/x)(1+3/x)

now as x >>inf
all of the fractions go to zero, leaving....
15 years ago
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evaluate the limit as x approaches positive and negative infinity (x^2+6x+8)/(x+3)^2

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