the ball will bounce when its height returns to zero. Use the given equation, plugging in the initial height and velocity
h = -16t^2 + 47t
= t(-16t+47)
clearly h=0 when t=0 (the ball is kicked) and t=47/16 (the ball bounces)
So, the ball is in the air 47/16 seconds.
A soccer player kicks a ball and gives it an initial upward velocity of 47 feet per second. If everyone waits for the ball to bounce, how long will it be in the air? (Use the vertical motion formula, h= -16tsquared + vt + c, where h is the height of the ball will be at time t, v is the initial upward velocity, and c is the starting height.
PLEASE HELP! I DON'T UNDERSTAND!
THANKS SO MUCH!
1 answer
1 answer