Asked by Anonymous
if a soccer player kicks a ball at an angle of 36 degrees and it lands 31.4 meters away. what is the initial velocity of the ball
Answers
Answered by
bobpursley
hf=hi+vivertical*timeinair- 9.8 time^2
0=0+V*sin36*t-9.8 t^2
so what is time in air.
timeinair= 31.4/Vhorizontal= 31.4/Vcos36
Vsin36*t=9.8t^2
Vsin36=9.8 t
V= 9.8/sin36 * 31.4/Vcos36
V= sqrt (9.8*31.4/sin36cos36)
0=0+V*sin36*t-9.8 t^2
so what is time in air.
timeinair= 31.4/Vhorizontal= 31.4/Vcos36
Vsin36*t=9.8t^2
Vsin36=9.8 t
V= 9.8/sin36 * 31.4/Vcos36
V= sqrt (9.8*31.4/sin36cos36)
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