Asked by Shane
Find the area of the triangle with sides 8.6 cm, 9.1cm and 9.7cm. First find the size of one of the angles.
Answers
Answered by
Henry
Use the law of cosines.
cosA = (-a^2+b^2+c^2)/2bc.
cosA=(-(8.6)^2+(9.1)^2+(9.7)^2)/176.54 =
0.58310.
A = 54.33o.
Area = 0.5*bc*sinA.
Area=0.5*9.1*9.7*sin(54.33) = 35.9 cm^2
cosA = (-a^2+b^2+c^2)/2bc.
cosA=(-(8.6)^2+(9.1)^2+(9.7)^2)/176.54 =
0.58310.
A = 54.33o.
Area = 0.5*bc*sinA.
Area=0.5*9.1*9.7*sin(54.33) = 35.9 cm^2
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