Question

Al2(SO4)3+6KOH-->2Al(OH)3+3K2SO4

a)How many grams of potassium hydroxide are needed to completely react with 870 mg of aluminum sulfate?

b)If you want to make 7.00 grams of potassium sulfate, how many grams of aluminum sulfate would you need to react?

c)How many grams of aluminum hydroxide would you make if you completely react 1.23*10^-5 moles of aluminum sulfate?

Answer 1

convert grams to moles
Each mole of Al2(SO4)3 requires 6 moles of KOH and produces 2 moles of Al(OH)3

Now just plug in your numbers and chug out the answers.