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2Fe(SO4)3+6koh--->2Fe(OH)3+3k2(SO4)

if you started with 12.3 g of potassium hydroxide and a sufficient amount of iron III sulfate how many grams of iron III hydroxide will form?

1 answer

mols KOH = grams/molar mass
mols KOH = ?mols Fe(OH)3---Use the coefficients in the balanced equation.
g Fe(OH)3 = mols x molar mass.
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