Asked by Chris

For z1 = 4cis(7pi/6)and z2 = 3ci(pi/3), find z1 · z2 in rectangular form.

A.12 − 12i
B.-12 − 12i
C.12 + 12i
D.12i
E.-12i
Answered by Steve
just multiply moduli and add arguments:
(4)(3)cis(7pi/6 + pi/3)
12 cis 3pi/2

(E)
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