How do I solve these for x?

Question

1) 1+2log5x=7

2) logaX=3/2loga9+loga2

Answer 1

1.
is that ... 2log (5x) or is it ... 2log₅x ?

2. I will assume that 'a' is the base

log_ax = log_a(9^(3/2)) + log_a2
log_ax = log_a27 + log_a2
log_ax = log_a((27)(2))
x = 54