Asked by Keyshia
How do I solve these for x?
1) 1+2log5x=7
2) logaX=3/2loga9+loga2
1) 1+2log5x=7
2) logaX=3/2loga9+loga2
Answers
Answered by
Reiny
1.
is that ... 2log (5x) or is it ... 2log<sub>5</sub>x ?
2. I will assume that 'a' is the base
log<sub>a</sub>x = log<sub>a</sub>(9^(3/2)) + log<sub>a</sub>2
log<sub>a</sub>x = log<sub>a</sub>27 + log<sub>a</sub>2
log<sub>a</sub>x = log<sub>a</sub>((27)(2))
x = 54
is that ... 2log (5x) or is it ... 2log<sub>5</sub>x ?
2. I will assume that 'a' is the base
log<sub>a</sub>x = log<sub>a</sub>(9^(3/2)) + log<sub>a</sub>2
log<sub>a</sub>x = log<sub>a</sub>27 + log<sub>a</sub>2
log<sub>a</sub>x = log<sub>a</sub>((27)(2))
x = 54
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