Asked by Reen
how do you do the linear equation y + 9 =1/5x and 45 - 3y = 15x
Answers
Answered by
Bosnian
45 - 3 y = 15 x Divide both sides by 3
15 - y = 5 x Subtract 15 to both sides
- y = 5 x - 15 Multiply both sides by - 1
y = - 5 x + 15
y + 9 = ( 1 / 5 ) x
- 5 x + 15 + 9 = x / 5
- 5 x + 24 = x / 5 Subtract x / 5 to both sides
- 5 x + 24 - x / 5 = 0 Subtract 24 to both sides
- 5 x - x / 5 = - 24
- 25 x / 5 - x / 5 = - 24
- 26 x / 5 = - 24 Multiply both sides by 5
- 26 x = - 120 Divide both sides by - 26
x = - 120 / - 26
x = ( - 2 * 60 ) / ( - 2 * 13 )
x = 60 / 13
y = - 5 x + 15
y = - 5 * 60 / 13 + 15
y = - 300 / 13 + 15
y = - 300 / 13 + 195 / 13
y = - 105 / 13
Solutions :
x = 60 / 13
y = - 105 / 13
15 - y = 5 x Subtract 15 to both sides
- y = 5 x - 15 Multiply both sides by - 1
y = - 5 x + 15
y + 9 = ( 1 / 5 ) x
- 5 x + 15 + 9 = x / 5
- 5 x + 24 = x / 5 Subtract x / 5 to both sides
- 5 x + 24 - x / 5 = 0 Subtract 24 to both sides
- 5 x - x / 5 = - 24
- 25 x / 5 - x / 5 = - 24
- 26 x / 5 = - 24 Multiply both sides by 5
- 26 x = - 120 Divide both sides by - 26
x = - 120 / - 26
x = ( - 2 * 60 ) / ( - 2 * 13 )
x = 60 / 13
y = - 5 x + 15
y = - 5 * 60 / 13 + 15
y = - 300 / 13 + 15
y = - 300 / 13 + 195 / 13
y = - 105 / 13
Solutions :
x = 60 / 13
y = - 105 / 13
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