please Write the linear equation 3y=6x−18 in slope-intercept form

Answer 1

To write the equation \( 3y = 6x - 18 \) in slope-intercept form, which is \( y = mx + b \) (where \( m \) is the slope and \( b \) is the y-intercept), follow these steps:

1. Divide both sides by 3 to solve for \( y \): \[ y = \frac{6x - 18}{3} \]

2. Simplify the right side: \[ y = \frac{6x}{3} - \frac{18}{3} \] \[ y = 2x - 6 \]

So, the equation in slope-intercept form is: \[ y = 2x - 6 \]

Here, the slope \( m = 2 \) and the y-intercept \( b = -6 \).

Answer 2

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Answer 3

It seems like you might be looking for a way to express the final result clearly. The slope-intercept form of the equation \(3y = 6x - 18\) is:

\[ y = 2x - 6 \]

If you are looking for something different or have another question, please let me know!