Question
A 1600 kg vehicle moves with a velocity of 19.5 m/s. Calculate the power required to reduce the velocity to 3.20 m/s in 11.0 s.
I don't know this one the only thing I know is p=w/t
I don't know this one the only thing I know is p=w/t
Answers
andrew
dont know if its correct but its something.
p=w/t
W=KE=(1/2)m(v)^2
p=(.5mv^2)/t
p_inital=(.5(1600)(19.5))/11=27654watts
p_final=(.5(1600)(3.2))/11=744.7...watts
(p_final)-(p_inital)=26909.27...watts
maybe? idk
p=w/t
W=KE=(1/2)m(v)^2
p=(.5mv^2)/t
p_inital=(.5(1600)(19.5))/11=27654watts
p_final=(.5(1600)(3.2))/11=744.7...watts
(p_final)-(p_inital)=26909.27...watts
maybe? idk