Asked by bob
a 1600-kg vehicle moves with a velocity of 19.5 m/s. calculate the power required to reduce the velocity to 3.20 m/s in 11.0 s
Answers
Answered by
Damon
decrease in kinetic energy = (1/2)(1600) (19.5^2 - 3.2^2) = 800(370) = 296,000 Joules
296,000 Joules/11 s = 26,900 watts
= about 27 kilowatts
296,000 Joules/11 s = 26,900 watts
= about 27 kilowatts
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