Call lactic acid HL and sodium lactate NaL.
..........HL ==> H^+ + L^-
I.........0.140...0...0.0085
C.........-x......x.....x
E.......0140-x....x...0.0085+x
Substitute into the Ka expression for HL and solve for x = (H^+).It may be necessary to solve a quadratic.
Then %ion = [(H^+)/0.140]*100 = ?
Calculate the percent ionization of 0.140 M lactic acid in a solution containing 8.5×10−3 M sodium lactate.
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