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Determine the percent ionization of a 2.45 M solution of benzoic acid
10 years ago

Answers

DrBob222
Let HBz be bezoic acid

..........HBz ==> H^+ + Bz^-
I.........2.45....0......0
C..........-x.....x......x
E.......2.45-x....x......x

Substitute the E line into Ka for HBz (you will need to look that up in your text/notes) and solve for x
Then %ionization = [(H^+)/2.45]*100 = ?
10 years ago

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