Let HBz be bezoic acid
..........HBz ==> H^+ + Bz^-
I.........2.45....0......0
C..........-x.....x......x
E.......2.45-x....x......x
Substitute the E line into Ka for HBz (you will need to look that up in your text/notes) and solve for x
Then %ionization = [(H^+)/2.45]*100 = ?
Determine the percent ionization of a 2.45 M solution of benzoic acid
1 answer