x^2-2x-8,=0
graph an appropriate quadratic function
(x-4)(x+2)<=0
x-4<=0 x+2<=0
answer
x<=4 and x,=-2
2 answers
Yes, that is correct but it says graph ;/.
it looks like you starting statement was
(x-4)(x+2) ≤ 0
there are two critical values on the x-axis. At x=4 and at x=-2
Mark those with a solid dot.
Now you have 3 sections of that graph
1. the part to the left of -2
2. between -2 and 4
3. to the right of 4
So simply test for some value in each of these sections and see if it satisfies the inequation.
If it does, so will every other number in that section.
I found -2 ≤ x ≤ 4
so draw a solid line from -2 to 4 on your graph,
(x-4)(x+2) ≤ 0
there are two critical values on the x-axis. At x=4 and at x=-2
Mark those with a solid dot.
Now you have 3 sections of that graph
1. the part to the left of -2
2. between -2 and 4
3. to the right of 4
So simply test for some value in each of these sections and see if it satisfies the inequation.
If it does, so will every other number in that section.
I found -2 ≤ x ≤ 4
so draw a solid line from -2 to 4 on your graph,
5 answers