Asked by Dora
A solution is made by mixing 20.0 mL of toluene C6H5CH3d=0.867gmL with 150.0 mL of benzene C6H6d=0.874gmL.
Assuming that the volumes add upon mixing, what are the molarity (M) and molality (m) of the toluene
Assuming that the volumes add upon mixing, what are the molarity (M) and molality (m) of the toluene
Answers
Answered by
DrBob222
Use density to determine mass toluene, then convert mass to mols toluene.
Use density to determine mass 150.0 mL benzene,
Then molality toluene = #mols/kg solvent.
molarity = mols/L solution.
Post your work if you get stuck.
Use density to determine mass 150.0 mL benzene,
Then molality toluene = #mols/kg solvent.
molarity = mols/L solution.
Post your work if you get stuck.
Answered by
Dora
i still got it wrong
0.867 g/mol= x/ 20 ml x= 17.94 g
0.874 g/mol= x/ 150 mil x= 131.1 g
toluene 17.904 g x 1 m/ 92.14 g/ mol= .194 m
benzee 131.1 g x 1m/78.1121 g/mol = 1.68 m
.194 m Toluene/ .1311 kg = 1.48
0.867 g/mol= x/ 20 ml x= 17.94 g
0.874 g/mol= x/ 150 mil x= 131.1 g
toluene 17.904 g x 1 m/ 92.14 g/ mol= .194 m
benzee 131.1 g x 1m/78.1121 g/mol = 1.68 m
.194 m Toluene/ .1311 kg = 1.48
Answered by
DrBob222
0.867 g/mol= x/ 20 ml x= 17.94 g<b>You made a math error here. I get 17.34 g</b>
0.874 g/mol= x/ 150 mil x= 131.1 g<b>This is OK. </b>
toluene 17.904 g x 1 m/ 92.14 g/ mol= .194 m <b>This should be 17.34 g toluene. And that divided by 92.14 = 0.188 mols toluene. Then 0.188/kg solvent = 0.188/0.1311 = 1.434 which I would round to 1.43 for molality toluene.</b>
benzee 131.1 g x 1m/78.1121 g/mol = 1.68 m
.194 m Toluene/ .1311 kg = 1.48 <b>see above for correction.
For molarity of toluene, we have 0.188 mols/150 mL or 0.188/0.150 L = 1.25 mols/L = 1.25 M.</b>
0.874 g/mol= x/ 150 mil x= 131.1 g<b>This is OK. </b>
toluene 17.904 g x 1 m/ 92.14 g/ mol= .194 m <b>This should be 17.34 g toluene. And that divided by 92.14 = 0.188 mols toluene. Then 0.188/kg solvent = 0.188/0.1311 = 1.434 which I would round to 1.43 for molality toluene.</b>
benzee 131.1 g x 1m/78.1121 g/mol = 1.68 m
.194 m Toluene/ .1311 kg = 1.48 <b>see above for correction.
For molarity of toluene, we have 0.188 mols/150 mL or 0.188/0.150 L = 1.25 mols/L = 1.25 M.</b>
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